(1/3)^x-2=(1/3)^2

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Solution for (1/3)^x-2=(1/3)^2 equation: 



(1/3)^x-2=(1/3)^2

We move all terms to the left:

(1/3)^x-2-((1/3)^2)=0



Domain of the equation: 3)^x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/3)^x-2-((+1/3)^2)=0

We calculate fractions


()/3^x*3)^2))+(-3^x/3^x*3)^2))-2=0

We can not solve this equation

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